math
Re: math
? This is baby steps compared to optimization algorithms i've used in matlab and mathematica. This is nothing but application of the total differential. It only really shows the benefit when used with differential equations. It is just a classic math problem: use the brain-challenging method to solve the problem instead of something simple like plug/chug. As for what i use at work, it's much different than this, as i use FEA which relies on tensor operators and spits out the resulting tensor for my engineering calculations.
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Re: math
I tried to follow this 1.15 exercise but still can't get the right answer. Should be 18,46%. Also does this 10% mean +-5% or +-10%
Could you please try to solve this one and send me the solution?
Could you please try to solve this one and send me the solution?
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Re: math
10% means +/- 10%
Too lazy to use LaTeX, so I'm just going to write it out here. I'm renaming the variables x_1, x_2, x_3 to x, y, z, respectively.
dC = (2x+y)dx + (4y+x+z)dy + (6z+y)dz
Substitute x = 20, y = 10, z = 10, dx = 2, dy = 1, dz = 1 to get dC = 240
Compute C(20,10,10) = 1300
240/1300 = 18.46%
Too lazy to use LaTeX, so I'm just going to write it out here. I'm renaming the variables x_1, x_2, x_3 to x, y, z, respectively.
dC = (2x+y)dx + (4y+x+z)dy + (6z+y)dz
Substitute x = 20, y = 10, z = 10, dx = 2, dy = 1, dz = 1 to get dC = 240
Compute C(20,10,10) = 1300
240/1300 = 18.46%
duck
imo
imo
Re: math
iNcog wrote:Vinyanyérë wrote:10% means +/- 10%
Too lazy to use LaTeX, so I'm just going to write it out here. I'm renaming the variables x_1, x_2, x_3 to x, y, z, respectively.
dC = (2x+y)dx + (4y+x+z)dy + (6z+y)dz
Substitute x = 20, y = 10, z = 10, dx = 2, dy = 1, dz = 1 to get dC = 240
Compute C(20,10,10) = 1300
240/1300 = 18.46%
wait so you just divide dC by 1300?
why does noissance's 1.15 exercise talk about distance?
Typo, 1.16 is the problem you need to look at and yeah like above ^
Error = dC(20,10,10)/C(20,10,10)
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- Ninja
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Re: math
Where this 1300 comes from?
I'm rly noob at this stuff
edit: aaa just value of function with plugged it shit. was just confused. thanks a lot!!!
I'm rly noob at this stuff
edit: aaa just value of function with plugged it shit. was just confused. thanks a lot!!!
- Vinyanyérë
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Re: math
iNcog wrote:Vinyanyérë wrote:10% means +/- 10%
Too lazy to use LaTeX, so I'm just going to write it out here. I'm renaming the variables x_1, x_2, x_3 to x, y, z, respectively.
dC = (2x+y)dx + (4y+x+z)dy + (6z+y)dz
Substitute x = 20, y = 10, z = 10, dx = 2, dy = 1, dz = 1 to get dC = 240
Compute C(20,10,10) = 1300
240/1300 = 18.46%
wait so you just divide dC by 1300?
why does noissance's 1.15 exercise talk about distance?
It's solving a slightly different problem. I didn't actually verify that 240/1300 is solving what the question is asking for, I'm just assuming it is since it divides into the answer.
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imo
imo
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Re: math
1300 is when you plug in 20,10,10 to the original function. dC gives you the approximate change in cost when you factor in the error. dx1 = 0.1 x1, dx2 = 0.1 x2, dx3 = 0.1x3.
@iNcog
@Vinyanyérë
@iNcog
i need more lighting in the room, cant see the keyboard properlyiNcog wrote:notification
@Vinyanyérë
what do you study/have studied?Vinyanyérë wrote:notification
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Re: math
@noissance
I was ECE+Math for undergrad, now EE for grad school. Though I'm leaving grad school soon to do other stuff.noissance wrote:notification
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imo
imo
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Re: math
Finishing up my masters portion of grad school, going for a doctorate. My research is in the field of thin film deposition atm, i want to research magnetic nanoparticles next.
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Re: math
My TA for both of my engineering courses this year was in my spring break group last year so that made my HW grades a bit better this semester #networking
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